Question

let A&B are two events with p(A)=2/3,P(B)=1/4 and P(AnB)=1/12 then P(A/B) is equal to?​

Answer 1

P(A')=1/4 so P(A)=3/4

P(AUB)'=1/6, P(AUB)=5/6

P(A∩B)=1/4

P(AUB)=P(A)+P(B)-P(A∩B)=3/4+P(B)-1/4

5/6=1/2+P(B)

P(B)=2/6=1/3

P(A)*P(B)=1/3*3/4=1/4=P(A∩B)

A and B are independent but not equally likely

$bts \: exo$