Let a and b are two real numbers such that, sina+sinb =(√2)/2 and cos a+ cosb=(√6)/2. Find (i) cos (a-b) and (ii) sin(a+b)
siddhartharao77:
i got cos(a-b)= 1/2 and sin(a+b)= root3/2? is it correct?
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Cos (a-b) = √2
Sin (a+b) = √3/2
Sin (a+b) = √3/2
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