Question

let A and B are two sets such that n(A)=20 ,n(B)=25 and n(AuB)=35 then find n(AnB)?​

Answer 1

Answer:

Step-by-step explanation:

There are 10 elements in a but not in b.

There are 10 elements in both a and b.

There are 6 elements in b but not in a.

So, the total number of elements in the union of a and b is 26.

This illustrates the general result that n(a ∪ b) = n(a) + n(b) - n(a ∩ b) :

20 + 16 - 10 = 26.

Answer 2

Answer:

n(AuB)=10

Step-by-step explanation:

n(AuB)=n(A)+n(B)-n(AnB)

35=20+25-n(AnB)

35=45-n(AnB)

-10=-n(AnB)(minus and minus gets cancelled)

n(AnB)=10