Let A and B be any two events defined on a sample space S with P(AUB)=3/4, P(A bar) =2/3 and P(A intersection B) =1/4, find P(A) ,P(B) and P(A intersection B bar)
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GIVEN :–
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• P(AUB) = ¾
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TO FIND :–
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• P(A) , P(B) &
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SOLUTION :–
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• We know that –
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• So that –
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• Now Let's fine –
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▪︎ Now Let's find P(B) –
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• Put the values –
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Answered by
24
Answer:
Given:
p(AUB)=3/4,
P(Ā)=2/3
p(AnB)=1/4
To find:
P(A), P(B) and P(ĀnBbar)
Solution:
As we know that,
1)P(A)+P(Ā)=1
P(A)+2/3=1
P(A)=1-2/3
P(A)=1/3
2) From the addition theorem,
P(AUB)=P(A)+P(B)-P(AnB)
3/4=1/3+p(B)-1/4
P(B)=3/4+1/4-1/3
P(B)=1-1/3
P(B)=2/3
3)P(ĀnB bar)=1-P(AUB)=1-3/4=1/4
Step-by-step explanation:
Hope it helps you.......
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