Question

Let a and b be distinct real numbers for which a/b + a+10b/b+10a=2. the value of a/b is equal to :
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Answer 1

Answer:

ok I am telling you

= 5

the answer is 5

please mark it brainliest

Answer 2

Given : relation between a and b,

$\frac{a}{b}=\frac{a+10b}{b+10a}=2$

To find : value of $\frac{a}{b}$.

Step-by-step explanation:

Consider the relation,

$\frac{a}{b}=\frac{a+10b}{b+10a}=2$

$\implies \frac{a}{b}=2-\frac{a+10b}{b+10a}$

$\implies \frac{a}{b}=2-\frac{\frac{a}{b}+10}{1+10\frac{a}{b}}$

letting $\frac{a}{b}=x$ we get,

$x=2-\frac{x+10}{1+10x}$

$\implies 10x^2-18x+4=0$

$\implies 5x^2-9x+4=0$

$\implies (x-1)(5x-4)=0$

$\therefore x=1,\frac{4}{5}$

That is value of $\frac{a}{b}$ is 1 and $\frac{4}{5}$.