Let a and b be real numbers such that x4+2x3−x2+ax+b=(Q(x))2 for some polynomial Q(x). What is the value of a + b?
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Answer:
Step-by-step explanation:
x^-4 =0 => x=+/-2.
f(x)=ax^4+2x^3–3x^2+bx
f(2)=16a+16–12+2b=0
or 8a+b= -2…………(1)
f(-2)=16a-16–12–2b=0
8a-b=14…………..(2)
On adding eq.(1) & (2)
16a =12 => a = 12/16 = 3/4
Put a = 3/4 in eq. (1)
6+b=-2 =>b = -8
a =3/4 , b = -8 , Answer
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