Question

Let a and b be respectively the lower and upper boundaries of a class interval in a grouped frequency distribution with continuous classes. What will be the mid value of the class interval next to it?
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Answer 1

Given :   a and b be respectively the lower and upper boundaries of a class interval in a grouped frequency distribution with continuous classes.

To find :  mid value of the class interval next to it

Solution:

a and b be respectively the lower and upper boundaries of a class interval in a grouped frequency distribution with continuous classes

Mid value of that group = (a + b)/2

and class interval range = b - a

Hence next class lower limit would be   b

and next class upper limit would  be   b  + ( b - a)  =  2b - a

mid value of the next class interval  = (b + 2b - a) / 2  

= (3b - a)/2

Another method to find next class mid value  = last class mid value + Class interval range

= (a + b)/2  + (b - a)

= (a + b  + 2b - 2a)/2

= (3b - a)/2

the mid value of the class interval next to it = (3b - a)/2

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