Let a and b be respectively the lower and upper boundaries of a class interval in a grouped frequency distribution with continuous classes. What will be the mid value of the class interval next to it?
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Answers
Given : a and b be respectively the lower and upper boundaries of a class interval in a grouped frequency distribution with continuous classes.
To find : mid value of the class interval next to it
Solution:
a and b be respectively the lower and upper boundaries of a class interval in a grouped frequency distribution with continuous classes
Mid value of that group = (a + b)/2
and class interval range = b - a
Hence next class lower limit would be b
and next class upper limit would be b + ( b - a) = 2b - a
mid value of the next class interval = (b + 2b - a) / 2
= (3b - a)/2
Another method to find next class mid value = last class mid value + Class interval range
= (a + b)/2 + (b - a)
= (a + b + 2b - 2a)/2
= (3b - a)/2
the mid value of the class interval next to it = (3b - a)/2
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