Let A and B be sets.if A intersection X=B intersection X=fi and A union X=B union X for some set Z,show that A=B (Hints A=A intersection (A union X), B=B intersection (B union X) and use distributive law)
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Let A and B be two sets such that A∩X=B∩X=ϕ and A∪X=B∪X for some set X.
To show: A=B
It can be seen that
A=A∩(A∪X)
=A∩(B∪X) (A∪X=B∪X)
=(A∩B)∪(A∩X) (Distributive law)
=(A∩B)∪ϕ (∵A∩X=ϕ)
=A∩B ......(1)
Now, B=B∩(B∪X)
=B∩(A∪X) (∵A∪X=B∪X)
=(B∩A)∪(B∩X) (Distributive law)
=(B∩A)∪ϕ (∵B∩X=ϕ)
=B∩A
=A∩B ......(2)
Hence, from (1) and (2), we get
A=B.
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