Question

Let A and B be two events with P(Ac) =0.3, P (B)=0.4 and P(A ∩B’) =0.5 Then P(B/(AUB’)) is equal to

Answer 1

A and B are two independent events with P (A u B) = 0.9 and p(A) = 0.6 Find P(B)?

5.2k Views ·

Suppose A and B are independent events, if p(a) =0.3 and p(b) =0.9 what is P(AB)?

Suppose A and B are events of a sample space S with P(A) = 0.42, P(B) = 0.34, and P (A or B) = 0.53. How do I find the probability of B and the complement of A?

Given two mutually exclusive events A and B such that P(A) = 0.4 and P(B) = 0.3 find P(A) or P(B)?

For two independent events, A and B, we are given Pr (A union B) = 0.9 and Pr(A)=0.4. What is Pr(B)?

For two events A and B,P(B) =0.3,P (A but not B) =0.4 and P (not B) =0.6.The event A and B are?

P (AuB) =P(A)+(B) - P(A)×P(B)

Or 0.9=0.6+P(B) - 0.6 P (B)

Or P(B)×(1-0.6)=0.9-0.6

Or P(B)= 3/4

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If two events A and B are independent then,

P(A n B)= P(A).P(B)

P(A u B)= P(A)+P(B)-P(A n B)

Since A and B are independent, so

P(A u B)= P(A)+P(B)-P(A).P(B)

0.9=0.6+P(B)-(0.6 x P(B))

P(B)(1–0.6)=0.3

P(B)=3/4= 0.75

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