Let A and B be two finite sets such that n(A)=20,n(B)=28 and n(AUB)=36,find n(A∩B)
Answers
Answered by
4
Answer:
n(AUB)=n(A)+n(B)-n(AnB)
36=20+28-n(AnB)
n(AnB)=12
Answered by
5
n(A ∩ B) = 12
Given:
n(A) = 20
n(B) = 28
n(A U B) = 36
To Find:
n(A ∩ B)
Calculating:
To solve these type of questions we use the formula:
n(A ∩ B) = n(A) + n(B) - n(A ∪B)
Substituting all the values known to us into this formula we get:
= 20 + 28 - 36
= 48 - 36
= 12
Therefore, the value of n(A ∩ B) = 12.
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