Question

Let A and B be two sets and U be their universal set. If n(U) = 120, n(A) = 42, n(B) = 50 and n (A intersection B ), then find,
n (PUQ) and n(PUQ) where P = A - B and Q = A intersection B.​

Answer 1

$Question$

Let A and B be two sets and U be their universal set. If n(U) = 120, n(A) = 42, n(B) = 50 and n (A intersection B ), then find,

n (PUQ) and n(PUQ) where P = A - B and Q = A intersection B.​

$ANSWER$

The cartesian product of A and B=A× B={(a,b):(a∈A) and (b∈B)}

Number of elements in A×B=∣A×B∣=∣A∣.∣B∣=pq

Any relation from A to B is a subset of A×B.  

Hence number of relations from A to B is the number of subsets of A×B

=2  

∣A×B∣

=2  

pq

HENCE THE ANSWER IS $pq$

:)

Answer 2

Answer:

hope my attachment answer is correct