let A and B be two sets such that n(A)=0.16 n(B)=0.14 n(AUB)=0.25 then n(AnB) is equal to fill ups
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GIVEN :
Let A and B be two sets such that n(A) = 0.16, n(B) = 0.14, n(A\bigcup B)=0.25n(A⋃B)=0.25 .
TO FIND :
The value of n(A\bigcap B)n(A⋂B)
SOLUTION :
Given that let A and B be two sets such that n(A) = 0.16, n(B) = 0.14, n(A\bigcup B) = 0.25n(A⋃B)=0.25 .
The formula is given by :
n(A\bigcup B)=n(A)+n(B)-n(A\bigcap B)n(A⋃B)=n(A)+n(B)−n(A⋂B) .
Substitute the values in the formula we get,
0.25=0.16+0.14-n(A\bigcap B)0.25=0.16+0.14−n(A⋂B) .
n(A\bigcap B)=0.16+0.14-0.25n(A⋂B)=0.16+0.14−0.25
=0.30-0.25=0.30−0.25
=0.05=0.05
∴ n(A\bigcap B)=0.05n(A⋂B)=0.05
∴ the value of n(A\bigcap B)n(A⋂B) is 0.05
hope it helps you
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b one is right answer may it helps you
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