Let A and B be two sets such that n(A)=20, n(AuB)=41, n(AnB)=2
find n(B), n(A-B) and n(B-A)
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Answer:
Given:
n(A)=20
n(AUB)=41
n(AnB)=2
n(B)=?
n(AUB)= n(A)+n(B)-n(AnB)
41=20+n(B)-2
41=18+n(B)
41-18=n(B)
23=n(B)
n(A-B)= 20-23
=-3
n(B-A)=23-20
=3.
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