Let A and B be two sets such that n(A)=5, n(AUB)=9, n(A∩B)=2; find n(B)
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Answer:
n(AUB)= 9 n(A) = 5 n (ANB) then n(B) = 6
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n(AUB) =n(A) +n(B) -n(AnB)
9 = 5 +n(B) - 2
9 = n(B) +3
+3 taking to left side
9- 3= n(B)
6 = n(B)
therefore n(B) = 6
I hope this will help you
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