let a and b events with p(a)=0.2, p(b)=0.08. are a and b independent?
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Step-by-step explanation:
x^3/9y^2 multiplied by 27y/x^5
27y*x^3/9y^2*x^5
3*x^3/y*x^5
3/y*x^2
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Answer:
P(A)=0.5 and P(AB)=0.8
When A and B are independent events,
P(A∩B)=P(A)×P(B)
⇒P(A)+P(B)−P(A∪B)=0.5×q
⇒0.5+q−0.8=0.5q
⇒0.5q=0.3
⇒q=0.6
When A and B are mutually exclusive events
P(A∩B)=0
P(A)+P(B)=P(A∪B)
0.5+p=0.8
⇒p=0.3
Hence the ratio of q and p is 2
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