Let A = {∅} and B = P(A), then A∩B is
(a) { ∅, {∅} } (b) {∅} (c) ∅ (d) {0}
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Option ( a ) is correct.
Reason :
Given A = { { } }
n( A ) = 1 ,
B = P( A ) = { { } , { { } } }
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