Question

Let a and ß be the zeroes of p(x) = 16x2 - 44x + 18.
(a) Find the value of a + B.
(b) Find the value of aß.

Answer 1

Answer:

dude that shouldn't be 16x 2 . Just saying all right

still I'll explain the concept.

if an equation is in the form of

P(x) = ax² + bx + c , where a, b and C are real no.s and a is not equal to zero. Such an equation is called a quadratic equation.

If A(alpha) and B(beta) are zeroes of P(x) then,

A + B' = - b/a

and AB = c/a.

PS. symbols of alpha and beta are different.

No option don't blame me