Question

let, a = b

a^2 = ab

a^2 - b ^2 = ab - b^2 { subtracting b^2 both sides}

(a + b) (a - b) = b(a - b)

a + b = b

b + b = b
2b = b

2 = 1

{1 cannot be 2 show me the mistakes in the above proof }

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Answer 1

Answer:

At the first step

a^2= ab

a×a= ab

a=b will left

That is given above

HP.

Or

From 4th line

(a+b) (a-b) = b(b-a)

(a+b) (0)=b(0)

0=0

H. P

BOTH R CORRECT..