Question

Let a, b ∊ ℝ and a² + b² ≠ 0. Suppose S = {z ∊ ℂ: z = 1/a + ibt, t ∊ ℝ, t ≠ 0}, where i = √-1. If z = x + iy
and z ∊ S, then (x, y) lies on
(A) the circle with radius 1/2a and centre (1/2a, 0) for a > 0, b ≠ 0
(B) the circle with radius -1/2a and centre (-1/2a, 0) for a < 0, b ≠ 0
(C) the x-axis for a ≠ 0, b = 0
(D) the y-axis for a = 0, b ≠ 0

Answer 1

Answer:

explain

Step-by-step explanation:

Answer 2

Answer:

I actually don't know the answer