Let A, B and C be sets such that Φ ≠ A ∩ B ⊂₋ C. Then which of the following statements is not true?
(A) If (A – C) ⊂₋ B, then A ⊂₋ B (B) If (A – B) ⊂₋ C, then A ⊂₋ C
(C) (C ∪ A) ∩ (C ∪ B) = C (D) B ∩ C ≠ Φ
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facebook the other one in this case the first place for
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Let A, B and C be sets such that the Φ ≠ A ∩ B ⊆ C. Then the statement which isn't true is:
(A) (A – C) ⊆ B, then A ⊆ B
This can be found within the following ways:
- Let us assume, A = { 5 , 6 , 7 , 8 }, B = { 7 , 8 , 9 , 10 }
and C = { 5 , 6 , 7 , 8 , 11 , 12 }
- Here, A ∩ B = { 7 , 8 } ⊆ C
- Since, A - C = Φ ⊆ B
- Also, A ⊄ B
- So, the incorrect statement out of the given statements is -
If ( A – C ) ⊆ B, then A ⊆ B
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