Question

let a b are roots of x²-6x=b,(b>0) and |a|,|b| are roots of x²+px+q=0 the minimum value of (p²-8q) is equal to​

Answer 1

Answer:

8

Step-by-step explanation:

a+b=6 eq1

ab=-b

therefore a=-1

put a=-1 in eq 1

b=7

put |a| as x in x²+px+q=0 as it is a root

that is

1+p+q=0 eq2

similarly put |b|

49+7p+q eq3

simultaneously solve eq2 and eq3

you will get q as 7 and p as -8

put values of q and p in (p²-8q)

and you get 8 as the answer