Question

let a,b be two positive real numbers such that a^2+b^2=2then the maximum value of (a+b)^2=​

Answer 1

Step-by-step explanation:

A and B are the two positive real numbers

a²+b²=2

If, we taken 1 as tje value of both a and b

Then,

a²+b²=2

1²+1²=2

1+1=2

Then the value of (a+b)²

=a²+2ab+b²

=1²+2×1×1+1²

=1+2+1

=4

So, the maximum value of (a+b) ²=4