Question

Let A, B, C be the centres of three circles
of equal radii; draw them so that each
one of them passes through the centre of
the other.​

Answer 1

Step-by-step explanation:

Let us draw two circles of same radius which are passing through the centres of the other circle.

Here, point A and B are the centres of these circles and these circles are intersecting each other at point C and O.

In quadrilateral ADBC,

AD=AC(Radius of circle centered at A)

BC=BD(Radius of circle centered at B)

As radius of both circles are equal, therefore, AD=AC=BC=BD

Hence, ADBC is a rhombus and i an rhombus, the diagonals bisect each other at 90

o

.

Hence,

AB

and

CD

are at right angles.

plz make me as a brainliest.