Question

Let a, b, c be the length of the sides of a triangle and x be the in radius . Show that
x<a^2+b^2+c^2 / 3(a+b+c)





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Answer 1

Answer:

Let a, b, c be the length of the sides of a triangle and x be the in radius . Show that

x<a^2+b^2+c^2 / 3(a+b+c)

Step-by-step explanation:

Let a, b, c be the length of the sides of a triangle and x be the in radius . Show that

x<a^2+b^2+c^2 / 3(a+b+c)