Question

let a,b,c be the side of a right triangle, where c is the hyptenuse .the redius of the circle which touches the sides of the triangle is

Answer 1

Answer:.

Let the circle touches the sides AB,BC and CA of triangle ABC at D, E and F

Since lengths of tangents drawn from an external point are equal We have

AD=AF, BD=BE and CE=CF

Similarly EB=BD=r

Then we have c = AF+FC

⇒ c = AD+CE

⇒ c = (AB-DB)(CB-EB)

⇒ c = a-r +b-r

⇒ 2r =a+b-c

r =( a+b-c)/2

Answer 2

Answer:

if the hypotenuse is c then the radius of cicle be c/2

because the triangle is touching to the circle therefore hypotenuse becomes the diameter of the circle

Step-by-step explanation: