let a b c be the three vectors of magnitude 3, 4, and 5 respectively if one is perpendicular to the sum of the other two vectors, then |a + b + c | =
all a, b, c have bars
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Given, a.(b+c)=0,b.(c+a)=0,c.(a+b)=0
Adding these, 2(a.b+b.c+c.a)=0 Also a
2
= a
2∣ =9,b
=25
Now (a+b+c)
2
=Σa
2
+2Σa.b=9+16+25+0+=50
∴∣a+b+c∣=5
2
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