let a,b,c be three positive real numbers such that abc is not equal to 1, (ab)^2=(bc)^4=(ca)^x=abc, then x=?
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Taking logarithm gives:
2(loga+logb)=4(logb+logc)=x(logc+loga)=loga+logb+logc
then taking,
2(loga+logb)=loga+logb+logc
and
4(logb+logc)=loga+logb+logc
we would get loga+logb−logc=0 &
3logb+3logc−loga=0 and by solving these two equations we get
log b = −log c
similarly log a= −log b then the solution becomes obvious......as x=1/2
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