Question

)let a, b, c, d and e be distinct integers in ascending order such that(76-a)(76-b)(76-c)(76-d)(76-e) = 1127.  what is a + b + c + d?



a. 30



b. 274



c. 334



d. 136

Answer 1

therefore answer of the above question should be 274. option B

Answer 2

Given : a, b, c, d and e be distinct integers in ascending order such that(76-a)(76-b)(76-c)(76-d)(76-e) = 1127.

To find :  a + b + c + d

Solution:

1127 =  7 * 7  *  23

But we we need  5 Distinct  numbers

1127 =  (-1) (1) (-7)(7) * 23  

a, b, c, d and e be distinct integers in ascending order

=>  (76-a) , (76-b) , (76-c), (76-d) , (76-e)  are in descending order

76 -a  = 23 =>  a  =  53

76 - b  = 7  => b  = 69

76 - c  = 1  =>  c  = 75

76 - d = -1  =>  d  = 77

76 - e  = 7  =>  e  = 83

a + b + c + d = 53 + 69 + 75 + 77  = 274

a + b + c + d + 2 =  53 + 69 + 75 + 77 + 83   = 357

a + b + c + d =  274

option b is correct

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