Question

Let A,B,C is a right angled triangle at B, AC=13 cm & AB=12 cm. Find the values of sinC, tanA & secC ​

Answer 1

Step-by-step explanation:

In △ABC,

⇒ ∠B=90 [ Given ]

⇒ AB=12cm and AC=13cm [ Given ]

Here, O is center of a circle and x is a radius.

⇒ (AC) ^2 = (AB)^2 +(BC) ^2 [ By Pythagoras theorem ]

⇒ (13) ^2 =(12) ^2 +(BC) ^2

⇒ 169=144+(BC) ^2

⇒ (BC) ^2 =25

∴ BC=5cm

Sin C = Opposite Side/Hypotenuse

= AB/AC

= 12/13

Tan A = Opposite Side/Adjacent Side

= BC/AB

= 5/12

Sec C = Hypotenuse/Opposite Side

= AC/AB

= 13/12

IF YOU FIND THIS ANSWER HELPFUL PLEASE MARK ME AS THE BRAINLIEST.

HOPE IT HELPS YOU! ✌✌