Math, asked by vss2ds, 1 year ago

Let A,B,C represent angles in a triangle, and a,b,c the sides opposite those respective angles. How many possible triangles can exist, given that a=10, b=30, A=150?

1). 1
2). 0
3). 2
4). 3

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Answers

Answered by Golda
0
Solution :-

The correct answer of this question is the option (2) '0'.

Explanation -

Given : m∠a = 10°, m∠b = 30° and m∠c = 150°

We all very well know that the sum of all the three angles of any triangle is always equals to 180°. But here in this question, the sum of the three angles of the given triangle is more than 180°.

⇒ 10° + 30° + 150° = 190°   

Which is not possible.

So, no possible triangle or 0 triangle can exist according to the given information in this question.

So, the option (2) is correct.

Answer.
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