Let A = {b, d, e, g, h} and B = {a, e, c, h } verify that n(A-B) =n(A) –n(A∩B)
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n(A-B) = {b,d,g}
n(A) = {b, d, e, g, h}
n(A∩B) = {e,h}
n(A-B) = n(A) -n(A∩B)
{b,d,g} = {b, d, e, g, h} - {e,h}
{b,d,g} = {b,d,g}
hope it will help you dear ☺️
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