Question

Let A = {b, d, e, g, h} and B = {a, e, c, h}. Verify that n (A – B) = n (A) – n (A ∩ B).

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Answer 1

Hello, Buddy!!

Refer The Attachment ⬆️

Hence, Proved

• $\longmapsto\;\bold{n (A – B) = n (A) – n (A ∩ B)}$

$\boxed{\tt{@MrMonarque}}$

Hope It Helps You ✌️

Answer 2

Step-by-step explanation:

Given :-

A = {b, d, e, g, h} , n(A) = 5

B = (a, e, c, h}      , n(B) = 4

To Prove :-

n(A - B) = n(A) - n(A ∩ B)

Solution :-

A ∩ B = {b, d, e, g, h} ∩ {a, e, c, h}

          = {e, h}

∴n(A ∩ B) = 2                                             (1)

A - B =  {b, d, e, g, h} - {a, e, c, h}

        =  {b, d, g}

∴n(A - B) = 3                                               (2)

By substituting (1) and (2) in n(A - B) = n(A) - n(A ∩ B), we get-

n(A - B) = 5 - 2

            = 3 = n(A - B)

Hence, proved that, n(A - B) = n(A) - n(A ∩ B)