Let A={b,d,e,g,h} and B={a,e,c,h} verify that n(A-B)=NCB)-(ANB)
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Step-by-step explanation:
A = {b, d, e, g, h), B = {a, e, c, h} A ∩ B = {b, d, g} n(A ∩ B) = 3 … (1) A ∩ B = {e, h} n(A ∩ B) = 2, n(A) = 5 n(A) – n(A ∩ B) = 5 – 2 = 3 … (2) Form (1) and (2) we get n(A – B) = n(A) – n(A ∩ B)
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Answered by
1
Answer:
Step-by-step explanation:
A = {b, d, e, g, h), B = {a, e, c, h} A ∩ B = {b, d, g} n(A ∩ B) = 3 … (1) A ∩ B = {e, h} n(A ∩ B) = 2, n(A) = 5 n(A) – n(A ∩ B) = 5 – 2 = 3 … (2) Form (1) and (2) we get n(A – B) = n(A) – n(A ∩ B)
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