Question

Let A be a 3×3 matrix with real entries such that det(A)=6 and tr(A)=0. If det(A+I)=0 (I denotes 3×3 identity matrix), then the eigen values of A​

Answer 1

Step-by-step explanation:

If a,b,c are eigen values of A then a+1,b+1,c+1 are eigen values of A+I.Am i right? then we have a+b+c=0, abc=6 and (a+1)(b+1(c+1)=0.IS it possible to solve these equation to find a,b,and c. – mercy May 3 '14 at 3:07

Expand the product (a+1)(b+1)(c+1)=0 fully then the solution will emerge. – P