Let A be a non-singular square matrix of order 3×3. Then |adj(adjA)| is equal to
|A|^16
|A|^8
|A|^2
|A|^4
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Answer:
We know that
AadjA=∣A∣I
n
⇒∣AadjA∣=∣∣A∣I
n
∣
⇒∣A∣∣adjA∣=∣A∣
n
∣I
n
∣ (∵∣AB∣=∣A∣∣B∣;∣kA∣=k
n
∣A∣)
∣A∣∣adjA∣=∣A∣
n
∣I
n
∣ (Determinant of identity matrix is 1)
Dividing by ∣A∣, we get
⇒∣adjA∣=∣A∣
n−1
(Since, A is non-singular i.e.∣A∣
=0)
So, if A is a square matrix of order 3,
∣adjA∣=∣A∣
2
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