Physics, asked by Arunraj3796, 10 months ago

Let →A be a unit vector along the axis of rotation of a purely rotating body and →B be a unit vector along the velocity of a particle P of the body away from the axis. The value of →A. →B is
(a) 1
(b) −1
(c) 0
(d) None of these.

Answers

Answered by Anonymous
3

Answer:

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Answered by bhuvna789456
0

(c) 0

The value of →A. →B is zero

Explanation:

The unit vector A will be perpendicular to the unit vector B along the body's Particle P from its axis along the rotation axis of the strictly rotating body.

Mathematically ,

Given data  

Let A be a unit vector along a purely rotating rotational axis  

B be a unit vector along the speed of a body part P away from the axis

Angle between them = θ = 90°

Formula for dot product of two vectors is

A.B = |A| |B| Cos θ  [ A.B is the dot product . ]

Substitute the value of \theta, where \theta = 90°

A.B = |A| |B| Cos 90°  [cos 90° = 0 ]

A.B = |A| |B| × (0)

A.B = 0  

The value of →A. →B is zero (0) for the unit vector →A along the axis of rotation of a purely rotation body and another unit vector →B along the velocity of a particle P of the body away from the axis.

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