Let a be the hcf of 24 and 36, Find the 2 numbers a and b, such that d=24a+36b
RehanAhmadXLX:
what is d??
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Hey!
Small correction in the question!
Let a be the hcf of 24 and 36, Find the 2 numbers a and b, such that d=24a+36bd = HCF of 24 and 36
Now,
we have to find a and b such that d =24a + 36b
We can use Euclid division lemma!
24 = 2*12+0
36 = 24*1+12...........(i)
hence, HCF of 24 and 36 = 12
Nowm from (i) we get,
12 = 36 - 24
12 = 24(-1) + 36(1)
12 = 24(a) + 36(b)
hence, a = -1 and b = 1
Small correction in the question!
Let a be the hcf of 24 and 36, Find the 2 numbers a and b, such that d=24a+36bd = HCF of 24 and 36
Now,
we have to find a and b such that d =24a + 36b
We can use Euclid division lemma!
24 = 2*12+0
36 = 24*1+12...........(i)
hence, HCF of 24 and 36 = 12
Nowm from (i) we get,
12 = 36 - 24
12 = 24(-1) + 36(1)
12 = 24(a) + 36(b)
hence, a = -1 and b = 1
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