Question

Let A be the set of natural numbers which are multiples of 5 strictly less than 100, and B be the set of natural numbers which divide 100. What are the cardinalities of B \ A (the set of elements in B but not in A), A ∩ B and B?​

Answer 1

Answer:

Set A included: 5,10,15,20,25,30,35,40,45,50,55,60,65,70,75,80,85,90,95.

Set B included: 1,2,4,5,10,20,25,50,100

Set A Union Set B included :5,10,20,25,50 (numbers included in both set A and Set B such group is called union group)

Hope it helps you

Please Mark me as Brainliest

Answer 2

Step-by-step explanation:

Given: A be the set of natural numbers which are multiples of 5 strictly less than 100, and B be the set of natural numbers which divide 100.

To Find: The set of elements in B but not in A (B-A), A ∩ B and B

• We know, A Set is a well defined collection of objects or elements.
• In the given question, A is the set of natural numbers which are multiples of 5 strictly less than 100 and B is the set of natural numbers which divide 100. Hence,

       ⇒ Set A = {5, 10, 15, 20, 25, 30, 35, 40, 45, 50, 55, 60, 65, 70, 75, 80, 85, 90, 95}

      ⇒ Set B= {2, 4, 5, 10, 20, 25, 100}

• The intersection of A and B will include all the elements which are common to both A and B without an repetition.

     ⇒ A ∩ B = {5, 10, 20, 25}

• B-A includes all the  elements which are in B but not in A.

    ⇒ B-A = {2, 4, 100}

Hence, B-A = {2, 4, 100}, A ∩ B = {5, 10, 20, 25} and B= {2, 4, 5, 10, 20, 25, 100}.