let a factor and b vector be the two vectors of magnitude 10 units is if are inclined to the x-axis at angles 30 degree and 60 degree respectively find the resultant
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heya..
Let R be the magnitude of the resultant vector.
Rx = A cos30 + B cos60 = (10)(√3/2) + (10)(1/2) = 5(√3 + 1)
Ry = A sin30 + B sin60 = (10)(1/2) + (10)(√3/2) = 5(√3 + 1)
Angle between A and B is 300.
Therefore,
R = [(Rx)2 + (Ry)2 + 2(Rx)(Ry) cos30]1/2
=> R = 26.39 units
Angle made by the resultant with the X axis is,
tanΦ = Ry/Rx = 1
=> Φ = 450
Let R be the magnitude of the resultant vector.
Rx = A cos30 + B cos60 = (10)(√3/2) + (10)(1/2) = 5(√3 + 1)
Ry = A sin30 + B sin60 = (10)(1/2) + (10)(√3/2) = 5(√3 + 1)
Angle between A and B is 300.
Therefore,
R = [(Rx)2 + (Ry)2 + 2(Rx)(Ry) cos30]1/2
=> R = 26.39 units
Angle made by the resultant with the X axis is,
tanΦ = Ry/Rx = 1
=> Φ = 450
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