let A={factors of 24} and B={factors of 30} verify n(A-B)=n(A)-n(AnB)=n(AUB)-n(B)
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Step-by-step explanation:
A = { 1, 2 3, 4, 6, 8 , 12, 24 }
B = { 1, 2 ,3, 5, 6 ,10,15, 30 }
n ( A ) = { 8 }
n ( B ) = { 8 }
n ( A - B )
= ( 8 - 8 )
= 0
n ( A ) - n ( A ∩ B )
= 8 - 8
= 0
n ( A ∪ B ) - n ( B )
= 8 - 8
= 0
Hence it is proved.
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