Math, asked by catchmeifucan, 1 year ago

Let a>0, b>0 and c>0. Then both the roots of the eqaution a x^{2}  + b x + c + 0
a) are real and negative
b) have negative real parts
c)are ration numbers
d) none of these

Answers

Answered by abhi178
1
ax² + bx + c = 0 where a > 0 , b > o and c > o 
      use formula,
  x = { -b +_√(b² - 4ac) }/2a 
     = { -b - √(b² - 4ac)}/2a , { -b + √(b² -4ac) }/2a 
here a, b and c are real and positive so,
roots are real and negative 

Hence roots are  negative real parts . option (b) is correct .
Answered by Anonymous
1
Hi Friend,

Here is your answer,

             
ax²+bx+c=0  a > 0 , b > o and c > o 

  We will use formula
  x =>  -b +_√(b² - 4ac) /2a 

  => -b - √(b² - 4ac)}/2a , -b + √(b² -4ac) /2a 


So, the correct option is (B)
Have negative real parts.

Hope it helps you!
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