Let a>0, b>0 and c>0. Then both the roots of the eqaution
a) are real and negative
b) have negative real parts
c)are ration numbers
d) none of these
Answers
Answered by
1
ax² + bx + c = 0 where a > 0 , b > o and c > o
use formula,
x = { -b +_√(b² - 4ac) }/2a
= { -b - √(b² - 4ac)}/2a , { -b + √(b² -4ac) }/2a
here a, b and c are real and positive so,
roots are real and negative
Hence roots are negative real parts . option (b) is correct .
use formula,
x = { -b +_√(b² - 4ac) }/2a
= { -b - √(b² - 4ac)}/2a , { -b + √(b² -4ac) }/2a
here a, b and c are real and positive so,
roots are real and negative
Hence roots are negative real parts . option (b) is correct .
Answered by
1
Hi Friend,
Here is your answer,
ax²+bx+c=0 a > 0 , b > o and c > o
We will use formula
x => -b +_√(b² - 4ac) /2a
=> -b - √(b² - 4ac)}/2a , -b + √(b² -4ac) /2a
So, the correct option is (B)
Have negative real parts.
Hope it helps you!
Here is your answer,
ax²+bx+c=0 a > 0 , b > o and c > o
We will use formula
x => -b +_√(b² - 4ac) /2a
=> -b - √(b² - 4ac)}/2a , -b + √(b² -4ac) /2a
So, the correct option is (B)
Have negative real parts.
Hope it helps you!
Similar questions