Question

Let A=i A cosq-j A sinq , be any vector. Another vector B which is normal to A is

Answer 1

Solution:-Let the required vector be xcos∅i+xsin∅j

If the angle between the vector xcos∅i+xsin∅j and iAcosq-jAsinq is 90

then,

dot product will be equal to 0

so,

Axcos∅cosq-Axsinqsin∅=0

cos∅cosq=sinqsin∅

cot∅=tanq

cot and tan are equal at angle 45°

so ∅=q=45

putting this value we get

another VectorB we get

xi/√2+xj/√2=B

this will be required VectorB