let A is a nob singular matrix such that A^2 + A - I = 0
Answers
Answered by
1
Answer:
6l
Explanation:
Given A be non-singular matrix.
So inverse of A exist.
(A−2I)(A−4I)=0
(A
2
−2A−4A+8I)=0
(A
2
−6A+8I)=0
Multiplying by A
−1
we get
(A
2
−6A+8I)A
−1
=0
A−6I+8A
−1
=0
A+8A
−1
=6I
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