Question

Let a means minus (-), b means multiplied by (x), c means divided by (/) and d means plus (+). The value of 90 d 9 a 29 c 10 b 2 is:

Answer 1

Answer:

93.2

Step-by-step explanation:

a : subtract

b : multiply

c : divide

d : add

Now,

90 d 9 a 29 c 10 b 2 = 90 + 9 - 29 / 10 * 2

Applying the order of precedence of operators BoDMAS, we have

90 + 9 - 29 / 10 * 2 = 90 + 9 - 2.9 * 2 = 90 + 9 - 5.8 = 99 -5.8 =93.2

∴90 d 9 a 29 c 10 b 2 = 93.2

Answer 2

Answer:

Required value of the given is 93.2

Step-by-step explanation:

Given,

$90 \: d \: 9 \: a \: 29 \: c \: 10 \: b \: 2$

It is also given that a means minus (-), b means multiplied by (x), c means divided by (/) and d means plus (+).

So,

$90 + 9 - 29 \div 10 \times 2$

By BODMAS rule,we can solve this problem.

B means bracket

O means of

D means division

M means multiplication

A means addition

S means subtraction

Now,

$90 + 9 - 29 \div 10 \times 2 \\ = 90 + 9 - 2.9 \times 2 \\ = 90 + 9 - 5.8 \\ = 93.2$

Therefore, required value of the given is 93.2

This is a problem of BODMAS rule of Algebra part.

Some important Algebra formula,

a + b)² = a² + 2ab + b²

(a − b)² = a² − 2ab − b²

(a + b)³ = a³ + 3a²b + 3ab² + b³

(a - b)³ = a³ - 3a²b + 3ab² - b³

a³ + b³ = (a + b)³ − 3ab(a + b)

a³ - b³ = (a -b)³ + 3ab(a - b)

a² − b² = (a + b)(a − b)

a² + b² = (a + b)² − 2ab

a² + b² = (a − b)² + 2ab

a³ − b³ = (a − b)(a² + ab + b²)

a³ + b³ = (a + b)(a² − ab + b²)

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