Let a planet exist whose mass and radius are one third of that on the surface of earth. calculate the acceleration due to gravity at its surface if acceleration due to gravity on Earth is ge
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Answer:
Let a planet exist whose mass and radius are one third of that on the surface of earth. calculate the acceleration due to gravity at its surface if acceleration due to gravity on Earth is ge
Answered by
2
Explanation:
let the mass of earth be Me and radius of earth be Re.
ge=Gme/(Re)^2 --------- (1)
also
let mass of planet be M =Me/3
and radius of planet R=Re/3
g=Gm/(R)^2-------------(2)
g=GMe/3(Re/3)^2
g=GMe*9/3Re^2
g=3GMe/Re^2
divinding equation (1) by equation (2)
(ge)/(g)=GMe/(R)^2/3GMe/(Re)^2
ge/g=1/3
g=3ge
Therefore the acceleration due to gravity on the surface of planet is 3 times that of earth.
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