Let a sequence be defined by
3, an
a1
3an-1 + 1
for all n > 1.
Find the first four terms of the sequence.
Answers
Answered by
0
Answer:
3,10,31 and 94.
Step-by-step explanation:
ANSWER
We have, a
1
=3
and, a
n
=3a
n−1
+1 for all n>1.
Putting n=2,3 and 4, we get
a
2
=3a
1
+1=3×3+1=10
a
3
=3a
2
+1=3×10+1=31
and, a
4
=3a
3
+1=3×31+1=94
Hence, the first four terms of sequence are 3,10,31 and 94.
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