Math, asked by Tamannadagar5868, 1 year ago

Let A =\left \lgroup\begin{array}{ccc}1&0&0\\2&1&0\\3&2&1\end{array}\right\rgroup . If u₁ and u₂ are column matrices such that Au₁ = \left \lgroup\begin{array}{c}1\\0\\0\end{array}\right \rgroup and Au₂ = \left\lgroup\begin{array}{c}0\\1\\0\end{array}\right\rgroup, then u₁ + u₂ is equal to :
(a) \left\lgroup\begin{array}{c}-1\\1\\0\end{array}\right\rgroup(b) \left\lgroup\begin{array}{c}-1\\1\\-1\end{array}\right\rgroup(c) \left\lgroup\begin{array}{c}-1\\-1\\0\end{array}\right\rgroup(d) \left\lgroup\begin{array}{c}1\\-1\\-1\end{array}\right\rgroup

Answers

Answered by AISHRAJPUT
1

and u₂ are column matrices such that Au₁ = \left \lgroup\begin{array}{c}1\\0\\0\end{array}\right \rgroup and Au₂ = \left\lgroup\begin{array}{c}0\\1\\0\end{array}\right\rgroup, then u₁ + u₂ is equal to :

(a) \left\lgroup\begin{array}{c}-1\\1\\0\end{array}\right\rgroup(b) \left\lgroup\begin{array}{c}-1\\1\\-1\end{array}\right\rgroup(c) \left\lgroup\begin{array}{c}-1\\-1\\0\end{array}\right\rgroup(d) \left\lgroup\begin{array}{c}1\\-1\\-1\end{array}\right\rgroup

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