let a vector =2i(cap)+3j(cap)+4k(cap) and b vector=3i(cap)+4j(cap)+5k(cap) find angle between them.
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angle = tangent inverse ( vector Y )/(vector X)
= tangent inverse(2*2 + 3*3 + 4*4 )/(3*3+4*4+5*5)
= tangent inverse (0.58)=30.11
harshbhardwaj23:
say angle
30
how 30
taking tangent inverse of the magnitude of veritical and horizontal component of vector
edit your answer and do it on note book with diagram and attach it with your answer
hi
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