Let A={x∈N∣1<x<4},B={x∈W∣0⩽x<2} and C={x∈N∣x<3 } . Then verify that
A×(B∪C)=( A×B)∪( A×C)
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A×(B∪C)=( A×B)∪( A×C)+A×(B∪C)=( A×B)∪( A×C)
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