Let A = {x ∈ W | x < 2}, B = {x ∈ N |1 < x < 4} and C = {3, 5}. Verify that A × (B ∪ C) = (A × B) ∪ (A × C)
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Answer:
A={0,1},B={2,3,4} and C={3,5}
∪ is combination of two sets.
B∪C={2,3,4,5}
Now,
L.H.S=A×(B∪C)
={0,1}×(2,3,4,5}
={(0,2),(0,3),(0,4),(0,5),(1,2),(1,3),(1,4),(1,5)} ---- ( 1 )
R.H.S=(A×B)∪(A×C)
={0,1}×{2,3,4}∪{0,1}×{3,5}
={(0,2),(0,3),(0,4),(1,2),(1,3),(1,4)}∪{(0,3),(0,5),(1,3),(1,5)}
={(0,2),(0,3),(0,4),(0,5),(1,2),(1,3),(1,4),(1,5)} ---- ( 2 )
From ( 1 ) and ( 2 )
⇒ L.H.S=R.H.S
∴ A×(B∪C)=(A×B)∪(A×C)
Step-by-step explanation:
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